Complete combustion of one mole of sucrose (c12h22o11) should produce 11 moles of water

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The burning of sucrose has been studied extensively in order to understand the chemical reactions that occur when a fuel is oxidized. One molecule of sucrose (C12H22O11) will produce 11 moles of water, and carbon dioxide gas.

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This reaction can be expressed as follows: This equation shows that for every molecule of sugar burnt, there are two molecules produced from the combustion process. The first product is hydrogen gas which is given off as a result of oxidation on the initial side-chain COOH group. On the second side-chain OH group, once it has lost an oxygen atom we have H2O or water vapor which is a product of the combustion reaction.

The difference in mass between these two molecules, hydrogen gas and water vapor, is 11 grams per mole which are released as waste products from burning sucrose fuel. The total number of moles produced by this process can be calculated using equation (x). For every one molecule of sugar burnt there will be eleven moles produced for a total equal to 11 times 12 or 132 gms.

These gases are given off during the complete combustion reaction and they each have specific properties that contribute towards an understanding of what happens when something burns completely like how much heat it produces at different rates if you burn wood on your stovetop versus gasoline in an engine manifold while driving down the highway at 70mph.


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