This expression is simplified to 2-9y. We can combine the like terms and get -11y + 11. What is a simpler form of the expression? -11y+11=0. In other words, y has no effect on this situation because it cancels out in the equation. We cannot simplify any further than this.
It does not matter what value we assign to y for this particular problem. The answer will always be that there are zero solutions to our quadratic equation (x²±(b)³). This means that x could also be z or w without affecting anything at all about how an equation works. What we do need to worry about is whether b would have an affect on things if we were assigned a nonzero number for b.
The answer is yes; if we assign a number for b, then the equation would change in some way and there may be more than one solution to our quadratic equation! This means that y does have an affect on this situation (y²) because it modifies how the original function behaves and changes what numbers are allowed as solutions so we can no longer say “It doesn’t matter what value you put into x or y.” If you don’t believe me, try assigning different values for b. What happens? Let’s see: -11(x+b)+11=0 → -x+b=-(-11)*→ x≠±√-11*→ x={−√}.
